Practice Question Let R be the set of all real numbers and a function f-R-R be defined by f(x) = ax + b, where a, b are constants and a +0. Is f invertible? If it is so, find the inverse of f.
Select one correct option:
Inverse of f does not exist Correct 💪In-correct 🧐
f is one-to-one but not onto Correct 💪In-correct 🧐
U Inverse of f exists and f-1(x) =\(\frac{x-b}{a}\) Correct 💪In-correct 🧐
) f is onto but not one-to-one Correct 💪In-correct 🧐