Select one correct option:
1 1 <- CARRY 5 X 8 + 3 Y 4 + 2 Z 1 -------- 11 0 3 --------
Clearly, X + Y + Z + 1 = 10 => X + Y + Z = 9 Now, since neither of X, Y, Z can be zero, the value of Y will be maximum when X = Z = 1. => Max Y = 7
