#LetsPrepareATC
🏆 Prepare AAI - ATC Exam (2023) with ATC Gurus Mr. Paras Soni & Dr. Abhijit Sen
Campus
to
Corporate
Objective
Syllabus
Action Plan
Current Batch
Resources
Register
Guided
Projects
Data Science
API Development
MERN Stack
Mini Courses
Workshops
Explore
More
Technologies
Blogs
Testimonials
Free Tests
Interview Guides
Exams
Challenges
Resume/CV 101
Mock AI Interviews
AI Tools
Let's
Begin
Back to
Percentages
Dark Mode
Free Aptitude Question
Jack and Robert appeared in an examination. Robert scored 9 marks less than Jack. Jack’s score was 56% of the sum of their scores added together. Calculate their individual scores.
Select
one correct
option:
22 and 33
Correct 💪
In-correct 🧐
41 and 35
Correct 💪
In-correct 🧐
40 and 35
Correct 💪
In-correct 🧐
42 and 33
Correct 💪
In-correct 🧐
Report Bug/Issue
Previous Question
Next Question
Questions
Q. 1
Q. 2
Q. 3
Q. 4
Q. 5
Q. 6
Q. 7
Q. 8
Q. 9
Q. 10
Q. 11
Q. 12
Q. 13
Q. 14
Q. 15
Q. 16
Share to
Friend
October 02, 2023
/ #
427
/
Clear cache
Confirm the choice. 🧐
Are you sure with the current option selected?
Hint 💡
Report bug/issue to team 🐞
Options are wrong.
Formatting is wrong.
Answer is wrong.
Hint/Explanation is wrong.
Correct Answer 🎉
In-correct Answer 😔
Explanation
Let Robert’s score be x. Then, Jack’s score = x+9.
Now, x+9 = 56% of [(x+9) + x]
⇒ x+9 = 14/25 × (2x + 9)
⇒ 25 × (x+9) = 14 × (2x+9)
⇒ 25x + 225 = 28x + 126
⇒ 3x = 99 ⇒ x = 33.
Therefore, Robert scored 33 marks and Jack scored 42 marks.