Let the amount of work 1 man can do in 1 day be x and the amount of work 1 boys can do in 1 day be y.
Then, 6x + 8y = 1/10 and 26x + 48y = Β½.
Solving these two equations, we get: x = 1/100 and y = 1/200.
Amount of work done by 15 men and 20 boys in 1 day = 15/100 + 20/200 = ΒΌ.
Therefore, the answer is 4 days.